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因為有理數可以在數軸上表示,無理數不可以,當有理數和有理數相加時,答案仍能在數軸上表示,但有理數加無理數不能在數軸上表示出來,所以a+x=無理數
反正法. 設無理數p,有理數q 令r=p+q 如果r為有理數,則p=r-q 注意兩個有理數相减還是有理數,所以上面等式右邊是有理數. 而左邊是無理數. 從面衝突. 所以r只能是無理數. 證畢.
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