Given the function f (x) = ACOS (Wx + a) as shown in the figure, if f (90 °) = (- radical 3) / 2, then f (0)= key (2) / root Take a look

Given the function f (x) = ACOS (Wx + a) as shown in the figure, if f (90 °) = (- radical 3) / 2, then f (0)= key (2) / root Take a look

The period is (11 / 12-7 / 12) * 2 π = 2 / 3 π, so w = 3 / 2 π; it can be seen from the figure that the original image is shifted to the left by 1 / 12 π, that is, a / w = 1 / 12 π [f (x) = ACOS (w (x + A / W)) a / W is the translation size], so a = 1 / 8; after substituting f (90 °) = (- radical 3) / 2 into the original try to solve a, the final solution f (0) is OK

The known function f (x) = ACOS ^ 2 (Wx + 4 + 1) (a > 0, w > 0,0)

It's not + 4, it's + FAI
The conditions are not enough. Fai can't work it out
Finally, only f (x) = 3 / 2 + 3cos ((π / 2) x + Fai + 1) / 2

Given the function f (x) = ACOS (ω x + φ) as shown in the figure, f (tt / 2) = - 2 / 3, then f (x) is

The minimum positive period is 2 π 3
Note that F 2 is π 2 and π 7, so note that F 2 is π 3,
So f 2 π 3 = - F π 2 = 2 / 3