A = 2 × 3 × N2, B = 3 × N3 × 5, (n is prime), then the greatest common divisor of a and B is______ The least common multiple is______ .

A = 2 × 3 × N2, B = 3 × N3 × 5, (n is prime), then the greatest common divisor of a and B is______ The least common multiple is______ .

A = 2 × 3 × N2, B = 3 × N3 × 5 (n is prime), so the greatest common divisor of a and B is 3 × N2; the least common multiple of a and B is 2 × 3 × N3 × 5; so the answer is: 3 × N2, 2 × 3 × N3 × 5
A = 2 × 3 × N 2, B = 3 × 5 × N 2 (n is prime), find the greatest common factor and least common multiple of ab
A = 2 * 3 * N2 = 12n, B = 3 * 5 * N2 = 30n, so the greatest common factor of 12n and 30n is 6N, and the least common multiple is 60N
The greatest common factor is 3 × N2. Least common multiple 3 × 5 × 2 × N2
Is the predicate of children singular or plural
complex
complex
In the plural
complex
It's plural. It's a collective noun.
Plural!
Child is singular.
Children is the plural of children
Complex number, pure imaginary number, who can do it?
We know that Z, W is a complex number, (1 + 3I) × Z is a pure imaginary number, w = 2 + I / Z, and the absolute value w = 5 times the root sign 2
Let z = a + bi a, B ∈ R
(1 + 3I) (a + bi) = a-3b + (3a + b) I is a pure imaginary number, so the real part a-3b = 0
If w = 2 + Z / I = 2 + b-ai = 2 + b-3bi, then | w | = √ [(2 + b) ^ 2 + (3b) ^ 2] = 5 √ 2, then B can be solved
If you want to express w = Z / (2 + I), then | w | = | Z | / | 2 + I | = √ (a ^ 2 + B ^ 2) / √ 5 = 5 √ 2, the solution is a = 15, B = 5
You write better..
That is to say, let w = a + bi, then z = (a + bi) (2 + I), substituting the above conditions, (1 + 3I) * the real part of Z is 0, the module of W is 5 times the root sign 2, two unknowns, two equations, should be able to solve
For the complex number Z = a + bi (a, B are real numbers), there is ()?
A.|z^2|>|z|^2
B.|z^2|=|z|^2
C.|z^2|z^2
Why? Not a?
Can you give a counterexample to prove that a holds?
Can't we use exclusion?
Is mother with children singular or plural?
Mother with children is the attributive of mother, so mother with children means "mother with children"
The subject is mother, so the predicate is singular
It depends on how you use it. Sometimes it's plural, sometimes it's singular with mother
Look at the content behind you, for example,
If a mother with a child can enjoy the subsidy, then it is singular, because the subsidy is given to the mother.
If the mother with the child is crossing the road, use the plural because the mother and the child are together,
Predicate application singular
Are you pregnant?
Yes, it is singular.
If Z is a complex number and iz = 2-3i is satisfied, then the module of complex number is my operation
Iz = 2-3i
So z = (2-3i) / I = - 2i-3
Izi = under root (- 2) &# 178; + 3 & # 178; = root 13
In the complex set, if a + 3I = 2-bi (a, B are real numbers), then the module of a + bi | a + bi | =
Because a + 3I = 2-bi
So a = 2,3 = - B
So a = 2, B = - 3
So | a + bi | = | 2-3i | = √ [2 ^ 2 + (- 3) ^ 2] = √ 13
a+3i=2-bi → a+bi=2-3i → |a+bi|=|2-3i| →√2²+3²=√13
[English] "every child" is "every child" or "every children"
every child
Every is followed by the singular as the third person singular
Every child is singular
Each of the children can also be singular
every child.every It is followed by a singular noun and a simple three predicate
English plural
Two German / British / Italian / Japanese / Chinese / Indian / American / French / Russian
1 Japanese / Chinese, their singular and plural are homomorphic
For example, "English man" is composed of "English" and "man", and its plural is English. Otherwise, s will be added directly. For example, "German" will be added s directly
Except for the above two cases, s is added directly
Are you satisfied with this answer? You should pay attention to the second situation above