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由題意知a=12,b=5,c=13 ∴焦點是F(±13,0) ∴垂線是x=13 ∴x=13與雙曲線的交點是(13,25/12) 故交點到一個焦點的距離=25/12,到另一個焦點的距離=√(26²;+(25/12)²;)=313/12
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