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設直線截距式是x/a+y/b=1(其中a>0且b>0), 因為直線過(1,2),則1/a+2/b=1, 三角形面積為4,則ab/2=4,即ab=8, 聯立解出a=2,b=4, 所以直線方程為x/2+y/4=1,即2x+y-4=0.
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