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設直線方程為:y-4=k(x-1),即y=kx+4-k 則直線與x軸、y軸的交點分別為:[(k-4)/k,0]、(0,4-k) 由於直線在第一象限內與坐標軸圍成三角形,則有(k-4)/k>0,4-k>0,由此得:k
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