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設直線l為x/a+y/b=1 被兩坐標軸截得的線段端點為A(a,0)B(0,b) p(-1.3)是直線l被兩坐標軸截得的線段的中點, 所以 (a+0)/2=-1 a=-2 (0+b)/2=3 b=6 直線l為x/(-2)+y/6=1化為一般式得 3x-y+6=0
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