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設直線l與Y軸交於A點,與X交於B點,則AOB為直角三角形,OP為中線,容易知道A點座標為(0,4),B點為(6,0),直線方程為Y=KX+B,得B=4,K=-2/3,所以直線l的方程為Y=-2/3*X+4
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