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由漸近線是Y=正負三分之二X得:y^2=4x^2/9,即:x^2/9-y^2/4=0, 故:可設所求方程是x^2/9-y^2/4=k,代入點(2,-3)得:4/9-9/4=k,k=-65/36, 所以:所求方程是:x^2/9-y^2/4=-65/36
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