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首先明白定義域x>0.再求導得:f*(x)=-2x+a-1/x=-1/x(2x^2-ax+1)=0有兩解.對於函數:g(x)=2x^2-ax+1=0在x>0有兩解.可以得到方程組:判別式=a^2-4*2*1>0,f(0)>0,對稱抽a/4>0…
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