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假設函數f(x)=8X^3-12X^2+6x+1在區間(-1,0)內至少有一個根 故有f(0)f(-1)<0 f(0)=1,f(-1)= -26 很明顯f(0)f(-1)<0成立 故方程8X^3-12X^2+6x+1==0在區間(-1,0)內至少有一個根
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