Contact us
Choose a category below so we can get back to you as quickly as possible.
令f(X)=8X^3-12X^2+6X+1 f(-1)=-8-12-6+1=-25<0 f(0)=1>0 函數在區間(-1,0)內是連續的 根據中值定理,在區間(-1,0)內至少存在一點使8X^3-12X^2+6X+1=0 所以方程8X^3-12X^2+6X+1=0在區間(-1,0)內至少有一個根
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.