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f(x)=sin[2^x-2^(1/x)]f'(x)=cos[2^x-2^(1/x)]* [2^x-2^(1/x)]' =[2^x*ln2-2^(1/x)*ln2*(1/x)']*cos[2^x-2^(1/x)] =[2^x+1/x²*2^(1/x)]ln2*cos[2^x-2^(1/x)]
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