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由基本不等式知 ab+1/ab≥2根號[ab*(1/ab)]=2 (當且僅當ab=1/ab,即ab=1時取=) 同理a/b+b/a≥2(當且僅當a/b=b/a,即a=b時取=) (a+1/b)(b+1/b) =ab+1/ab+a/b+b/a ≥4 (當且僅當a=b=1時取=)
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