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給出一個不用公式的解法:
兩邊取對數:y'=lnx,dy/dx=lnx,dy=lnxdx,兩邊積分得:y=x(lnx-1)+C.
先積分得,y=(y^2)/2+e^x,化簡y^2-2y+2e^x=0 (y-1)^2=1-2e^x,所以1-2e^x≥0,最後得x≤根號e
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