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y''-y=0的特徵方程為a^2-1=0,解是a=1或a=-1, 囙此通解是y=Ce^x+De^(-x). y''-y=e^x的特解設為y=e^x(ax), 則y'=ae^x(x+1),y''=ae^x(x+2), 代入方程得2ae^x=e^x,於是a=0.5, 特解是y=0.5xe^x. 最後得微分方程的通解是 y=Ce^x+De^(-x)+0.5xe^x.
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