Given (SiNx + cosx) / (SiNx cosx) = 3, find the value of TaNx, 2Sin? X + (SiNx cosx) 2

Given (SiNx + cosx) / (SiNx cosx) = 3, find the value of TaNx, 2Sin? X + (SiNx cosx) 2

(sinx+cosx)/(sinx-cosx)=3
sinx+cosx=3sinx-3cosx
sinx=2cosx
tanx=sinx/cosx=2
sinx=2cosx
The identity sin? X + cos? X = 1 is introduced
cos²x=1/5
sinxcosx=2cosxcosx=2cos²x=2/5
sin²x=1-1/5=4/5
The original formula = 2 × 4 / 5 + sin 2 x + cos 2 - 2 SiNx cosx
=8/5+1-4/5
=9/5