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記∠B,∠C的外角分別為∠1,∠2,則∠1=∠A+∠C,∠2=∠A+∠B∴∠1+∠2=∠A+(∠A+∠B+∠C)=80°+180°=260°又BO,CO為∠1,∠2的角平分線∴∠CBO=(1/2)∠1,∠BCO=(1/2)∠2∴∠CBO+∠BCO=(1/2)(∠1+∠2)=130°∴∠BOC=180…
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