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證:因為等邊三角形ABC,BD=CE,∠ABC=∠ACB,△ABD≡△BCE;∴∠BDA=∠BEC,∠FBD=∠BAD,∵三角形內角和=180°,∴∠BFD=∠ABD,∴△BDF相似於△BEC,∴∠BFD=∠BCE=60°=∠AFE(對頂角相等).
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