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ce為斜邊ab上的中線? S直角三角形abc=ac*bc/2=ab*cd/2 cd=ac*bc/ab=24/8=3 ce=ab/2=8/2=4【在直角三角形中,斜邊上的中線等於斜邊的一半】 de²;=ce²;-cd²;=4²;-3²;=7 de=√7.
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