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lim(X→1)[x³+kx-2]/(x-1)有極限值,說明x³+kx-2可被x-1整除,x³+kx-2=(x³-1)+kx-1,其中x³-1可被x-1整除,若kx-1能被x-1整除,則k只能等於1 lim(X→1)[x³+kx-2]/(x-1)=lim(X→1) x²+x+2=4
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