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∫xe^x/(x + 1)²;dx=∫[(x + 1)- 1]e^x/(x + 1)²;dx=∫e^x/(x + 1)dx -∫e^x/(x + 1)²;dx=∫e^x/(x + 1)dx -∫e^x d[- 1/(x + 1)]=∫e^x/(x + 1)dx + e^x/(x + 1)-∫1/(x + 1)d…
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