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∵對直線3x-4y+12=0令x=0,得y=3;令y=0,得x=-4∴直線3x-4y+12=0交x軸於A(-4,0),交y軸於B(0,3)∵所求的圓以AB為直徑∴該圓以AB中點C為圓心,半徑長為12|AB|∵AB中點C座標為(−4+02,0+32),即C(-2,32)1…
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