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∠DBC=2∠ABD,∠DCB=2∠ACD,∠BDC=α+2/3∠A,∠A=180-∠ABC-∠ACB=180-1.5∠DBC-1.5∠DCB∠BDC=180-∠DBC-∠DCB又∠BDC=α+2/3∠A=α+2/3(180-1.5∠DBC-1.5∠DCB)=α+120-∠DBC-∠DCB故α=60…
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