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y-3=k(x-4)所以直線恒過點A(4,3) 化簡圓的方程得(x-3)^2+(y-4)^2=13圓心為C(3,4)r=根號13 因為AC=根號2小於r=根號13 所以A點在圓內 囙此直線l與圓的位置關係是相交
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