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整理之後不難看出mx^2+4x+m+2在分母上,所以mx^2+4x+m+2不等於0,又因為開4次方,所以mx^2+4x+m+2大於0 綜上mx^2+4x+m+2大於0 則m大於0,判別式小於0 解出來m屬於(-1+根號5,正無窮)
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