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原式=[(ax-by)³;+(by-cz)³;]-(ax-cz)³;運用立方和公式x³;+y³;=(x+y)(x²;-xy+y²;)=[(ax-by)+(by-cz)][(ax-by)²;-(ax-by)(by-cz)+(by-cz)²;]-(ax-cz)³;=(ax-by+by-cz)[(ax-…
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