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由已知圓的方程為x2+y2+2ax-4ay+5a2-4=0則圓的標準方程為:(x+a)2+(y-2a)2=4故圓的圓心為(-a,2a),圓的半徑為2若曲線C:x2+y2+2ax-4ay+5a2-4=0上所有的點均在第二象限內,則a>0,且-a>2解得a>2故a的取值...
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