1 / 2xy + y2 + 1 + x2 - 1 / 2xy - 2xy - 1

1 / 2xy + y2 + 1 + x2 - 1 / 2xy - 2xy - 1


뭐?



분해 인수: x 2 - 2xy + y 2 - 6 x + 6 y + 9


= (x - y) 2 - 6 (x - y) + 9
= (x - y - 3)



(2x 2 - y2) - [2y 2 - (x2 + 2xy)] =...


3 (X & sup 2; - y & sup 2;) + 2xy