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∵AB∥DC,CE∥DA,∴四邊形AECD是平行四邊形,∴DA=CE=6,DC=AE=5,∠DAB=∠CEB,∴EB=AB-AE=8-5=3.又∵四邊形ABCD為等腰梯形,∴∠DAB=∠B,∴∠CEB=∠B,∴CE=CB=6,∴△CEB的周長為:CE+CB+EB=6+6+3=15
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