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延長ED到G,使DG=DE,聯接BG、FG∵BD=CD∠BDG=∠CDE∴△BDG≌△CDE∴BG=CE∵∠ADF=½;∠ADB∠ADE=½;∠ADC∴∠ADF+∠ADE=½;(∠ADB+∠ADC)=90°∵DE=DG∴EF=FG∵BG+BF>FG∴CE+BF>EF…
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