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y=4x^2設M坐標是(a,4a^2)4x-y-5=0M到直線距離=4a-4a^2-5/√17也就是求4a-4a^2-5的最小值4a-4a^2-5=4a^2-4a+5=4(a-1/2)^2+44(a-1/2)^2+4〉0所以4a^2-4a+5=4(a-1/2)^2+4且當a=1/2時有最小值所以M(1/2,1)...
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