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設第1個數為X1第2個數為X2第3個數為X3 X1+X2+X3=12 (X1)*(X1)+(X2)*(X2)=(X3)*(X3) 變形得X3=根號下X1的平方+X2的平方 解得X1為3 帶入 解得X1=3 X2=4 X3=5 檢驗. 最終結論X1=3 X2=4 X3=5
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