Contact us
Choose a category below so we can get back to you as quickly as possible.
∵O是AB、AC的垂直平分線的交點,∴點O是△ABC的外心.如圖,連接OB.則∠BOC=2∠A=104°.又∵OB=OC,∴∠OBC=∠OCB.∴∠OCB=(180°-∠BOC)÷2=38°,故答案是:38°.
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.