Sin(x+派/2)=1/3則cos(x+7派/12)的值為?

Sin(x+派/2)=1/3則cos(x+7派/12)的值為?


Sin(x+π/2)=cosx=1/3,則sinx=土2√2/3,cos(7π/12)=cos(π/3+π/4)=(√2-√6)/4,sin(7π/12)=(√2+√6)/4,∴cos(x+7π/12)=cosxcos(7π/12)-sinxsin(7π/12)=(√2-√6)/12幹(4+4√2)/12=(-4-3√2-√6)/12,…



cos^2 5π/12-sin^2 7π/12=?求詳細過程


con²;(5π/12)-sin²;(7π/12)=cos²;(5π/12)-sin²;(π-7π/12)=cos²;(5π/12)-sin²;(5π/12)=cos(2*5π/12)=cos(5π/6)=-(√3)/2