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(1)y=cos√x+2^x→y'=-sin√x·(√x)'+2^xln2=(-1/2)(sin√x)/√x+2^xln2.(2)y=cos[(√x)+2^x]→y'=-sin[(√x)+2^x]·((√x)+2^x)'=-sin[(√x)+2^x]·(1/(2√x))+2^xln2).不知道是哪一種可能....
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