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z=x2+y2-xy zx'=2x-y =0 zy'=2y-x =0 x=0 y=0 ∴點(0,0)是維一的駐點 ∴二元函數z=x2+y2-xy的極值點是(0,0)
y'=6x²;+12x-18=0 x=-3,x=1 y'開口向上 所以x1,y'>0,y是增函數 -3
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