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當x等於0時無解 當x等於非0的實數時等於1
(1+x分之1)除以x分之x的2次方-1 =x分之(x+1)×[(x+1)(x-1)]分之x =(x-1)分之1
Y=e的x次方-x y′=e的x次方-1 令y′
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