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lim(ax+b)/(x^2-3x+2) =lim(ax+b)/(x-1)(x-2) =-lim(ax+b)/(x-1) =-lim(ax-a+a+b)/(x-1) =-lim(a+(a+b)/(x-1))=2 x->1所以x-1->∞ 原式極限存在,所以a+b=0且-a+0=2 a=-2,b=2
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