If y + 2 is an increasing function, then x = 2 is an even function A、f(1)<f(5/2)<f(7/2) B、f(5/2)<f(1)<f(7/2) C、f(5/2)<f(7/2)<f(1) D、f(7/2)<f(1)<f(5/2) The process is because f (x + 2) is an even function, so the axis of symmetry of F (x) is x = 2. Why is the axis of symmetry x = 2?

If y + 2 is an increasing function, then x = 2 is an even function A、f(1)<f(5/2)<f(7/2) B、f(5/2)<f(1)<f(7/2) C、f(5/2)<f(7/2)<f(1) D、f(7/2)<f(1)<f(5/2) The process is because f (x + 2) is an even function, so the axis of symmetry of F (x) is x = 2. Why is the axis of symmetry x = 2?

The function y = f (x + 2) is even and the image is symmetric about the y-axis
Y = f (x) shifts 2 units to the left to get the image of y = f (x + 2)
Then y = f (x + 2) shifts 2 units to the right to get the image of y = f (x)
The image is symmetric with respect to the line x = 2
∵ y = f (x) is an increasing function on (0,2)
/ / y = f (x) is a decreasing function on (2,4)
Answer D, f (7 / 2) < f (1) < f (5 / 2)