If + F (x) is a even function (- F, x) = 0, then (f) (x) is equal to (- 0, f) = 0=

If + F (x) is a even function (- F, x) = 0, then (f) (x) is equal to (- 0, f) = 0=

From F (x + 2) = - f (x), f (2012) = - f (2010), f (2010) = - f (2008), so f (2012) = f (2008) = f (2004) =. = f (0) = log2 ^ 1 = 0
Similarly: because f (x) is an even function, f (- 2011) = f (2011) = f (2007) = f (2003) =. = f (3) = - f (1) = - log2 ^ 2 = - 1
So the final result is - 1